Answer:
-14.68 m/s
Step-by-step explanation:
You are given the height of the balloon that it is "dropped": 11 m. Since the final velocity of a projectile is 0 m/s at the top of its flight, we can say that the initial velocity is 0 m/s and the displacement is -11 m (the balloon "starts" at the top of its trajectory).
We know the acceleration of the balloon is -9.8 m/s².
Use this kinematic equation that relates all four variables (displacement, initial velocity, final velocity, acceleration):
Substitute known variables into the equation.
- v² = 0² + 2(-9.8)(-11)
- v² = 215.6
- v = √215.6
- v = 14.68332387
- v = 14.68
Since the positive direction is up, the velocity when it hits the ground must be negative. The balloon hits the ground with a velocity of -14.68 m/s.