Question

16.(2-3x)+x^2.(3x-2)=0

Answer 1

`x_(1) = - 1 \: . \: \: x_(2) = (2)/(3) . \: \: x_(3) = 1`

Explanation:

`(2 - 3x) + {x}^(2) (3x - 2) = 0 \\ 2 - 3x + {x}^(3) - 2 {x}^(2) = 0 \\ - (3x - 2) + {x}^(2) (3x - 2) = 0 \\ - (3x - 2)(1 - {x}^(2) ) = 0 \\ (3x - 2)(1 - {x}^(2) ) = 0 \\ 3x - 2 = 0 \\ 1 - {x}^(2) = 0 \\ x = (3)/(2) \\ x = - 1 \\ x = 1 \\`

`\boxed{\green{ x_(1) = - 1 \: . \: \: x_(2) = (2)/(3) . \: \: x_(3) = 1}}`