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Cho Q(x)=x^2+mx-12.Biết Q(-3)=0.tìm nghiệm còn lại

Cho Q(x)=x^2+mx-12.Biết Q(-3)=0.tìm nghiệm còn lại
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Cho Q(x)=x^2+mx-12.Biết Q(-3)=0.tìm nghiệm còn lại

User Oleksii Masnyi
by
7.9k points

1 Answer

2 votes

Answer: m=-1.

Explanation:


Q(x)=x^2+mx-12\ \ \ \ Q(-3)=0\ \ \ \ \ m=?\\Q(-3)=(-3)^2+m*(-3)-12=0\\9-3m-12=0\\-3m-3=0\\3m=-3\ |:3\\m=-1.

User Najma
by
8.2k points
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