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Y=1x^(2)+10x+22 line of symmetry

1 Answer

3 votes

Answer:

x = -5

Explanation:

We can use the below formula to find the line of symmetry.

( x - a )² + b

Here,

line of symmetry = +a

Vertex = +b

And now let us take a look at the given equation.

y = x² + 10x + 22

To find the line of symmetry from the given equation we have to make the given equation as the given formula.

Let us use the completing square method for that.

y = x² + 10x + 22

Put zero instead of y.

x² + 10x + 22 = 0

x² + 10x = -22

x² + 10x + 25 = -22 + 25

( x + 5 )² = 3

( x + 5 )² -3 = 0

Therefore,

line of symmetry of the line is = -5

x = -5

Y=1x^(2)+10x+22 line of symmetry-example-1
User Esboych
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