Question

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Dean is skateboarding. He starts at a speed of 0.5 m/s and speeds up to 4.0 m/s
to go off a ramp over a time of 5.0 seconds. What is Dean's acceleration?

Answer 1

`\huge\boxed{\sf a = 0.7 \ m/s^2}`

Step-by-step explanation:

Given Data:

Initial velocity =
`V_i` = 0.5 m/s

Final velocity =
`V_f` = 4 m/s

Time = t = 5 s

Required:

Acceleration = a = ?

Formula:

`\displaystyle a =(V_f-V_i)/(t)`

Solution:

Put the givens in the formula.

`\displaystyle a=(4-0.5)/(5) \\\\a = (3.5)/(5) \\\\a = 0.7 \ m/s^2\\\\\rule[225]{225}{2}`