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What are the zeros of g(x)= x³ + 6x² - 9x-54?
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What are the zeros of g(x)= x³ + 6x² - 9x-54?

User Cornwell
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1 Answer

4 votes

Answer:

3,-3

Explanation:

g(3)= (3)³+6(3)²-9(3)-54

= 27+54-27-54

=81-81

= 0

g(-3) = (-3)³+6(-3)²-9(-3)-54

= -27+54+27-54

= 27-27

= 0

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