Question

1) "If a = − 9 and b = − 6, show that (a−b) ≠ (b−a)."

2) (-3) + (-7) = (-7) + ______
3) Subtract − 134 from the sum of 38 and − 87.
4) Find the product of: 16 x (-36) + (-36) x -46
5) "Find each of the following products:i) (-12) x 0 x (-56) ii) (-654) x 1
6) "Verify a – (-b) = a + b for the following values of a and b.i) a = 15, b = 9
7) What will be the sign of the product, if we multiply 90 negative integers and 9 positive integers?


PLS GIVE IT FAST AND THE ONE WITH THE CORRECT ANSWER WILL GET MAXIMUM POINT AND A CROWN

Answer 1

1) -3 is not equal to 3

2) -3

3) -183

4) 1112

5) 0

6) see explanation

7) positive

Explanation:

1) "If a = − 9 and b = − 6, show that (a−b) ≠ (b−a)."

-9--6 -9+6= -3

-6--9 -6+9= 3

2) (-3) + (-7) = (-7) + ______

-3-7=-10 -10+7=-3

(-7)+ (-3) = -10

3) Subtract − 134 from the sum of 38 and − 87.

38+-87

38-87=-49

-49-134= -183

4) Find the product of: 16 x (-36) + (-36) x -46

16×-34= -544

-36×-46= 1656

-544+1656= 1112

5) "Find each of the following products:i) (-12) x 0 x (-56) ii) (-654) x 1

times zero is in the equation so it equals 0

6) "Verify a – (-b) = a + b for the following values of a and b.i) a = 15, b = 9

15-(-9)=

15+9=24

two negatives make a positive

5+9=24

24=24

7) What will be the sign of the product, if we multiply 90 negative integers and 9 positive integers?

positive, 90 is divisible by two so all of those cancel out into a positive and then a positive times a positive is positive