Answer:
30.8 g of CO2.
Step-by-step explanation:
Using malar masses of gasoline and carbon dioxide:
2 * (12*8 + 1*18) g gas yields 16(12 + 2*16) g of CO2
228........................................... 704 g CO2
1g ................................................ 704/228
10g .................................................... (704*10)/228 = 30.8 g.