Question

John wants to measure the height of a tree. His eye level is 6 feet from the ground. He walks exactly 100 ft from the base of

the tree and looks up. The angle from the Johns eye level to the top of the tree is 33º. How tall is the tree?

Answer 1

70.9 feets

Explanation:

From trigonometry:

tan θ = opposite /Adjacent

Opposite = tree height, y

Adjacent = vertical distance between eyelevel and tree

tan 33º = y/100

y = 100 * tan 33º

y = 100 * 0.6494075

y = 64.9 feets

Distance between John's eye level and the ground = 6 feets

Total tree height = 6 + 64.9 = 70.9 feets