Answer:
I think it's
2 HgO (s) → 2 Hg (l) + O2 (g)
Explanation:
This is an oxidation-reduction (redox) reaction:
2 HgII + 4 e- → 2 Hg0
(reduction)
2 O-II - 4 e- → 2 O0
(oxidation)
5.6m questions
7.3m answers