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14 votes
14 votes
Kiran, Mai, and Tyler went to their school carnival. They all won chips that they could exchange for prizes. Kiran won 2/3 as many chips as Jada, Mai won 4 times as many chips as Kiran. Tyler won half as many chips as Mai. If Jada won 42 chips, how many chips did Tyler, Kiran, and Mai each win?

User Noelicus
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1 Answer

2 votes
2 votes

Answer:

k = 28

m = 112

t = 56

Explanation:

From the question, the following equations can be derived

Kiran's chips (k) = 2/3 x J

Mai (M) = 4 x k

Tyler = 1/2 x M

If Jada won 42 chips, Kiran's chips (k) = 2/3 x 42 = 28

Mai = 4 x 28 = 112

Tyler = 1/2 x 112 = 56

User Boris Sokolov
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3.2k points