Question

At a teddy bear workshop, customers can select from black, brown, gold, white, blue, or pink for their bear's colors. If a father randomly selects two bear colors, what is the probability that he will select a white bear for his son and a pink bear for his daughter? The father cannot pick the same color for both bears.

Answer 1

`P(White\ and\ Pink) = (1)/(30)`

Explanation:

Given

Colors: Black, Brown, Gold, White, Blue, Pink

Required

P(White and Pink)

Since the father can not select the same color, then it is a selection without replacement.

So, we have:

`P(White\ and\ Pink) = [P(White)\ and\ P(Pink)]`

`P(White\ and\ Pink) = [P(White)\ *\ P(Pink)]`

This gives:

`P(White\ and\ Pink) = [(1)/(6)\ *(1)/(6-1)]`

`P(White\ and\ Pink) = [(1)/(6)\ *(1)/(5)]`

`P(White\ and\ Pink) = [(1)/(30)]`

`P(White\ and\ Pink) = (1)/(30)`