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How many zeroes are at the end of $42!$ (42 factorial)? (Reminder: The number $n!$ is the product of the integers from 1 to $n$. For example, $5!=5\cdot 4\cdot3\cdot2\cdot 1= 120$.)

User Saurav
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7 votes

Answer:

47 zeros

Explanation:

User Barcelona
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