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3. A current of 6.0 amperes flows through a light bulb when the voltage difference between the ends of the filament are 110 volts. What is the resistance?
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5 votes
3. A current of 6.0 amperes flows through a light bulb when the voltage

difference between the ends of the filament are 110 volts. What is the
resistance?

User Timo Haberkern
by
5.6k points

1 Answer

9 votes

Answer:

18.3Ω

Step-by-step explanation:

Resistance can be found using the formula:

Resistance =
(Voltage)/(Current )

Voltage = 110 volts

Current = 6.0 amperes

∴ Resistance =
(110)/(6)

= 18.3 Ω ( to nearest 3 significant figures)

User Pressacco
by
5.6k points
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