115k views
15 votes
Triangle E F G is shown. Angle G F E is a right angle. The length of G F is 3 and the length of E F is 4.6. Which equation could be used to find m∠E in △EFG? m∠E = cos–1(StartFraction 3 Over 4.6 EndFraction) m∠E = cos–1(StartFraction 4.6 Over 3 EndFraction) m∠E = tan–1(StartFraction 3 Over 4.6 EndFraction) m∠E = tan–1(StartFraction 4.6 Over 3 EndFraction)

2 Answers

8 votes

Answer:

The answer is c

Explanation:

User Tschale
by
8.6k points
12 votes

Answer:

m∠E = tan–1(StartFraction 3 Over 4.6 EndFraction)

Explanation:

Given the following

m<GFE = 90 degrees

GF = 3

EF = 4.6

The side opposite to m<E is GF

Adjacent side is EF

Using the SOH CAH TOA identity

tan theta = opp/adj

tan m<E =GF/EF

Substitute the given values

tan m<E = 3/4.6

m<E = tan^-1 (3/4.6)

Hence the required result is m∠E = tan–1(StartFraction 3 Over 4.6 EndFraction)

User GReX
by
8.4k points

Related questions

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories