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HELP!!!!
The measure of side BC =

HELP!!!! The measure of side BC =-example-1
User Ted Cohen
by
8.7k points

1 Answer

7 votes

Answer:

D

Explanation:

Using the cosine ratio and the exact value

cos45° =
(√(2) )/(2) , then

cos45° =
(adjacent)/(hypotenuse) =
(BC)/(AC) =
(BC)/(n) =
(√(2) )/(2) ( cross- multiply )

2BC = n
√(2) ( divide both sides by 2 )

BC =
(n√(2) )/(2) → D

User Andrew Newdigate
by
8.7k points

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