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A baseball "diamond" is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runner "out"? (Distance across the diagonal)
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A baseball "diamond" is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runner "out"? (Distance across the diagonal)

180 feet


13.4 feet


90 feet


127.3 feet

User Wronex
by
8.8k points

2 Answers

9 votes

Answer:it’s 127.3

Explanation:

User Merlino
by
8.3k points
5 votes
127.3 feet is what I would choose
User Christian H
by
9.1k points
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