Answer:
![\text{signals in the 1H NMR spectrum around 5.5 ppm}](https://img.qammunity.org/2022/formulas/chemistry/college/golu0a656xrurhbiw4km9fulv0t4wszzv5.png)
![\text{signals in the 13C NMR spectrum around 140 ppm}](https://img.qammunity.org/2022/formulas/chemistry/college/dnbe3dqpcr8qtrzs00wsxxj3die7kbkb2d.png)
![\text{stretches in the IR spectrum immediately above 3000 cm-1}](https://img.qammunity.org/2022/formulas/chemistry/college/pq3150zz95l009ya84t9rn5k1stydgpezk.png)
![\text{stretch in the IR spectrum at approximately 1650 cm-1}](https://img.qammunity.org/2022/formulas/chemistry/college/xto5nzsyo6enbpa3p9fd9235yobc2qgnpx.png)
Step-by-step explanation:
The spectroscopy of distributed alkenes is adequately not the same as those of alkanes in many occurrences to make it conceivable to perceive when a double bond is available. For instance, in the infrared range of 1-butene, the assimilation band close to 1650cm−1 is normal for the extending vibration of the double bond.
As a rule, the power and position of this band rely upon the design of the alkene; it changes with the level of at the double bond, with the presence of a second unsaturated gathering in formation with the first, and with the evenness of the replacement of the double bond.
SO, from the information given: the correct information is:
![\text{signals in the 1H NMR spectrum around 5.5 ppm}](https://img.qammunity.org/2022/formulas/chemistry/college/golu0a656xrurhbiw4km9fulv0t4wszzv5.png)
![\text{signals in the 13C NMR spectrum around 140 ppm}](https://img.qammunity.org/2022/formulas/chemistry/college/dnbe3dqpcr8qtrzs00wsxxj3die7kbkb2d.png)
![\text{stretches in the IR spectrum immediately above 3000 cm-1}](https://img.qammunity.org/2022/formulas/chemistry/college/pq3150zz95l009ya84t9rn5k1stydgpezk.png)
![\text{stretch in the IR spectrum at approximately 1650 cm-1}](https://img.qammunity.org/2022/formulas/chemistry/college/xto5nzsyo6enbpa3p9fd9235yobc2qgnpx.png)