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Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 80. It is known that the population standard deviation of test scores is 13. A random sample of 23 students take the exam. The mean score for this group is 71. a)Calculate the 90% confidence interval for the population mean test score. Give your answers to 2 decimal places.

User Tang
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Answer:

The 90% confidence interval for the population mean test score is between 66.54 and 75.46.

Explanation:

We have that to find our
\alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:


\alpha = (1 - 0.9)/(2) = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of
1 - \alpha.

That is z with a pvalue of
1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such


M = z(\sigma)/(√(n))

In which
\sigma is the standard deviation of the population and n is the size of the sample.


M = 1.645(13)/(√(23)) = 4.46

The lower end of the interval is the sample mean subtracted by M. So it is 71 - 4.46 = 66.54

The upper end of the interval is the sample mean added to M. So it is 71 + 4.46 = 75.46

The 90% confidence interval for the population mean test score is between 66.54 and 75.46.

User Ravi L
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