Question

1-нұсқа

1)Мына теңдеуге мәндес бір теңдеуді жазыңыз: 2x-1,2=3x+1,5 [1]
2) Берілген сан аралықтарының сан түзуінде кескіндеп, қиылысуы
мен бірігуін жазыңыз: (-оо; -3] және (-5;+oo)
ВТеңдеуді шешіңіз: а) 1,6(х - 3) = 0,8(х - 5)
ә) 13х+5=7 (6)
4) Теңсіздіктер жүйесінің бүтін шешімдерінің санын табыңыз:
[5]​

Answer 1

To solve the equation 2x-1,2=3x+1,5, start by isolating the variable x on one side of the equation. Simplify the equation by grouping like terms and then solve for x by performing the necessary operations. In this case, the solution is x=-2.7.

Step-by-step explanation:

To solve the equation 2x-1,2=3x+1,5, we need to isolate the variable x.

First, let's get rid of the decimal points by multiplying both sides of the equation by 10, so the equation becomes 20x-12=30x+15.

Next, let's group the terms with x on one side by subtracting 20x from both sides, which gives -12=10x+15.

Then, subtract 15 from both sides to isolate the variable x, so -12-15=10x.

Finally, simplify the equation to find the value of x: -27=10x. Divide both sides by 10 and you will get the solution, x=-2.7.