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Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.
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9 votes
Find the resultant of two forces of 4.0N and 6.0N acting at an angle of 160° to each other.

User Marco Bonzanini
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1 Answer

18 votes
18 votes


\star\sf \overrightarrow{A}=4N


\star\sf\overrightarrow{B}=6N

  • Angle=160


\boxed{\sf R=√(A^2+B^2+2ABcos\theta)}


\\ \sf\longmapsto R=√(4^2+6^2+2(4)(6)cos160)


\\ \sf\longmapsto R=√(16+36+48(-0.93))


\\ \sf\longmapsto R=√(52-44.6)


\\ \sf\longmapsto R=√(7.4)


\\ \sf\longmapsto R=2.7N

User Jonathan Plackett
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2.5k points
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