287,263 views
21 votes
21 votes
Just help me please

Just help me please-example-1
User Anho
by
2.7k points

2 Answers

10 votes
10 votes
just download photo math, it’s super easy and the answers are always right
Just help me please-example-1
User M A Salman
by
3.0k points
20 votes
20 votes


\left( (4)/(5) \right)^(-3)

There are a few ways to approach this.

My preference is to apply that -3 exponent to both the top and the bottom:


\left( (4)/(5) \right)^(-3) = (4^(-3))/(5^(-3))

I'd do that the same way, no matter whether the exponent outside was a postive or negative number.

Since it is a negative number, I remember that negative exponents mean that factor is on the wrong side of the fraction. So anything with a negative exponent will move to the other side.


(4^(-3))/(5^(-3)) = (5^3)/(4^3)

Be sure to make the exponents' signs change when you move them to the other side of the fraction.

Finally I would evaluate
5^3 and
4^3 on their own to get my answer.


(5^3)/(4^3) = (5 \cdot 5 \cdot 5)/(4\cdot 4 \cdot 4) = (~~~?~~~)/(?)

User Graham Povey
by
2.9k points