Question

Objects 1 and 2 attract each other with a electrostatic force of 36.0 units

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Answer 1

F' = 9F

Step-by-step explanation:

The complete question is "Objects 1 and 2 attract each other with a electrostatic force of 36.0 units. If the charge of Object 2 is tripled, then the new electrostatic force will be _____ units".

The electric force is given by :

`F=(kq_1q_2)/(r^2)`

If F = 36 units,

`36=(kq_1q_2)/(r^2)\ ...(1)`

If charges are tripled, q₁' = q₂' = 3q₁ and 3q₂

So,

`F'=(kq_1'q_2')/(r^2)\\\\F'=(k* 3q_1'* 3q_2')/(r^2)\\\\F'=9* (kq_1'q_2')/(r^2)\\\\F'=9F`

So, the new force becomes 9 times of the initial force.