Question

HELP PLS! I NEED TO GET THIS RIGHT! Curious Carl and his lab partner were conducting a variety of experiments to produce gases: hydrogen, oxygen, and carbon dioxide. In one experiment, they added a piece of magnesium ribbon to 10 milliliters of hydrochloric acid. They observed bubbles being produced and did a variety of tests to identify the escaping gas; it proved to be hydrogen The reaction is represented by the following equation:

Mg + 2HCL -> MgCL2 + H2(g)

Assuming STP, how many moles of hydrogen gas did Carl and his partner collect if they collected 5.6L?

Answer 1

0.25 mole of H₂

Step-by-step explanation:

The equation for the reaction is given below:

Mg + 2HCl —> MgCl₂ + H₂

From the question given above, we were told that the reaction produced 5.6 L of H₂.

Thus, we can obtain obtain the number of mole of H₂ that occupied 5.6 L at STP as follow:

1 mole of H₂ occupied 22.4 L at STP.

Therefore, Xmol of H₂ will occupy 5.6 L at STP i.e

Xmol of H₂ = 5.6 / 22.4

Xmol of H₂ = 0.25 mole

Therefore, 0.25 mole of H₂ were obtained from the reaction.