Question

Answer both questions with explanation and answer will give brain list

Answer 1

Answer: 10. 39.7 g
`CH_3OH`

11. 650 g of
`HgO`

Step-by-step explanation:

To calculate the moles, we use the equation:

`\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}`

a) moles of
`H_2`

`\text{Number of moles}=(5.0g)/(2.0g/mol)=2.5moles`

`CO(g)+2H_2(g)\rightarrow CH_3OH(l)`

According to stoichiometry :

2 moles of
`H_2` produce = 1 mole of
`CH_3OH`

Thus 2.5 moles of
`H_2` produce=
`(1)/(2)* 2.5=1.25moles` of
`CH_3OH`

Mass of
`CH_3OH=moles* {\text {Molar mass}}=1.25moles* 32g/mol=39.7g`

Thus 39.7 g of
`CH_3OH` will be produced from 5.0 g of hydrogen.

11.
`2HgO(s)\rightarrow 2Hg(l)+O_2(g)`

According to stoichiometry :

1 mole of
`O_2` is produced by = 2 moles of
`HgO`

Thus 1.50 moles of
`O_2` are produced by =
`(2)/(1)* 1.50=3moles` of
`HgO`

Mass of
`HgO=moles* {\text {Molar mass}}=3moles* 216g/mol=650g`

Thus 650 g of
`HgO` woukd be decomposed to produce 1.5 mol of oxygen