Question

Find the inverse of g(n) = - 3 - 1

Og-1 (n) = -(n-3)-1
9
9-1 (n) = In
g-1 (n) = (n + 1)3 + 3
Og-1 (n) = 3+n3

Answer 1

`g'(n) = -(n+1)/(3)`

Explanation:

Given

`g(n) = -3n - 1`

Required

Determine the inverse

`g(n) = -3n - 1`

Replace g(n) with y

`y = -3n - 1`

Swap positions of x and y

`n = -3y - 1`

Make y the subject

`3y = -n - 1`

`3y = -(n + 1)`

`y = -(n+1)/(3)`

Replace y with g'(n)

`g'(n) = -(n+1)/(3)`