Question

5. A car stops in 20 m. If it has an acceleration of-6m/s?,

how fast was it going before you started slowing down?

Answer 1

15.49 m/s

Step-by-step explanation:

We know that the stopping distance is ,

=> s = u²/2(-a)

So that ,

=> 20m = u² / 2* 6m/s²

=> u² = 240m²/s²

=> u = √240 m²/s²

=> u = 15.49 m/s

**Edits are welcomed**