Question

A compound is found to have a composition of 35.880% Cr, 21.076% P, and 43,545% O

What is the empirical formula of the compound?

Answer 1

Step-by-step explanation:

Cr=35.880/51=0.73≈0.7

P=21.076/31=0.67≈0.7

O=43.543/16=2.71

Divide each by 0.7 u get

Cr=1 ,P =1, O=4

Empirical formula is CrPO4