Question

How many grams of copper metal are required to react with 4.00 grams of silver

nitrate to produce copper (II) nitrate?

Answer 1

0.753 grams of copper metal are required to react with 4.00 grams of silver nitrate to produce copper (II) nitrate

Step-by-step explanation:

mass = moles * Mr

Equation of this reaction:

Cu(s) + 2AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

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Find moles of silver nitrate:

4 = moles * 170

→
`(2)/(85)` moles

• Here we "2" molar ratio before silver nitrate and "1" before copper metal, so copper metal has half the moles of silver nitrate. copper metal has
  `(2)/(85)` ÷ 2 =
  `(1)/(85)` moles

so find the mass of copper metal:

mass =
`(1)/(85)` * 64

mass of copper is 0.753 grams.