Answer:
V = 177.4 L.
Step-by-step explanation:
Hello there!
In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:
Thus, by solving for volume we obtain:
So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:
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