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A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?
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A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

User Ahmet Altun
by
4.7k points

1 Answer

6 votes

Answer:

x(x-4)(x+8)

Explanation:

Factor.

x(x^2+4x-32)

x(x-4)(x+8)

User Dianne
by
5.1k points
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