Question

Find the zeros of the function below.

\small -7x=x^2+12

Answer 1

read explanation

Explanation:

this is a quadratic equation

first, move the 7x over to the other side so that we have 0 on one side

x^2+7x+12=0

now, we can factor

turn 7x into 3x and 4x, so x^2+3x+4x+12=0

you can turn x^2+3x into x(x+3) and 4x+12 into 4(x+3)

so, our new equation is x(x+3)+4(x+3)=0

that can be turned into (x+4)(x+3)=0 via the distributive property

so, either x+4 or x+3 has to be equal to 0

so, x is either -4 or -3

hope this helped