Question

Find the value of the term in the arithmetic sequence.

Answer 1

`\dispalystyle a_1=-2 ~\\\\~ d=a_2-a_1=1-(-2)=3 \\\\ a_(9)=a_1+(9-1)d=-2+8d=-2+24=\boxed{22} \\\\\\ \huge\boxed{\mathfrak{Answer}:a_(9)=22}`

Answer 2

Formula to fimd the 9th term:-

`\tt a_(n) = a_(1) + (n - 1)d`

Where,

• 
  `a_(n)` is the Nth term
• 
  `a_(1)` is the first term of sequence
• 
  `n` is the term to be found
• 
  `d` is the common difference between terms

In our case,

• 
  `a_(1) = - 2`
• 
  `n = 9`
• 
  `d = 3`

Put the values,

`\tt a_(9) = - 2 + (9 - 1) * 3`

`\tt a_(9) = - 2 + 8 * 3`

`\tt a_(9) = - 2 + 24`

`\tt a_(9) = 22`