Question

What is the perimeter of a rectangle with a width of 3x+12 and a length of x²-2x+10?

Answer 1

2x^2 + 2x + 44

Explanation:

Perimeter = length times 2 + width times 2

so perimeter = 2(x^2 -2x + 10) + 2(3x +12)

then: (2x^2 - 4x + 20) + (6x + 24)

which equals 2x^2 + 2x + 44