Question

container has a volume of 28 L and a temperature of 45 ºC The volume is increased to 34 L. What is the new temperature of the gas

Answer 1

386.14 K ( 113.14 ºC)

Step-by-step explanation:

Initial Volume V1 = 28 L

Initial Temperature T1 = 45 + 273 = 318 K

Final Temperature T2 = ?

Final Volume V2 = 34 L

The relationship between these quantities is given by the charles law equation;

V1 / T1 = V2/ T2

T2 = V2 * T1 / V1

Inserting the values

T2 = 34 * 318 / 28

T2 = 386.14 K