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Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution
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Given the equation 2 Square root of x minus 5 = 2, solve for x and identify if it is an extraneous solution

User Suracheth Chawla
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1 Answer

6 votes

Answer:

Explanation:

2√(x-5) = 2

√(x-5) = 1

x-5 = 1

x = 6

User SaRaVaNaN DM
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