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Factor y^3-1 completely
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Factor y^3-1 completely

User Pasan Chamikara
by
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1 Answer

12 votes

Answer:

The answer is (y - 1)^3 = (y - 1) (y^2 + y + 1)

Explanation:


(y - 1)^(3) = (y - 1)( {y}^(2) + y \: \: 1 + {1}^(2) ) \\ \\(y - {1)}^(3) = (y - 1)( {y}^(2) + y + 1)

User M Tomczynski
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