Question

A toy projectile is fired vertically from the ground upward with a velocity of +29 meters per second. It arrives at its maximum altitude in 3.0 seconds. How high does the projectile go?

Answer 1

`\boxed{\text{\sf \Large 42 m}}`

Step-by-step explanation:

Use height formula

`\displaystyle \sf H=(u^2 sin(\theta)^2)/(2g)`

u is initial velocity

θ = 90° (fired vertically upward)

g is acceleration of gravity

`\displaystyle \sf H=(29^2 * sin(90 )^2)/(2 * 10)=42.05`