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Solve the equation please​

Solve the equation please​-example-1
User Asher
by
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1 Answer

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Answer: E) y = -25/13

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Work Shown:

Let x = log(y+2)

The given equation becomes

4x = 3x-log(13)

Solving for x leads to

4x-3x = -log(13)

x = -log(13)

Then substituting gets us

log(y+2) = -log(13)

log(y+2) = log(13^(-1)) .... use the rule that A*log(B) = log(B^A)

log(y+2) = log(1/13)

y+2 = 1/13 ................. used the rule if log(A) = log(B), then A = B

y = (1/13) - 2

y = (1/13) - (26/13)

y = (1-26)/13

y = -25/13 .... answer is choice E

For each step, the logs are the same base. The base doesn't matter. It can be base 10 or base 2 or base e. As long as the base stays consistent is all that matters. Also, the base cannot be 1, 0 or a negative number. The base can be any other real number.

User Scott Kirkwood
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