Answer:
Explanation:
The surface area of a rectangular prism is
A=2(xy+xz+yz), where x,y,z are the dimensions, in this case
A=2(8(8)+8(10)+8(10))
A=2(64+80+80)
A=2(224)
A=448in^2
So the minimum amount of wrapping paper is 448in^2
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