Question

I need help with this please. :)

Answer 1

9514 1404 393

Answer:

1. 2x
2. 2
3. 128x +640

Explanation:

1.

`\displaystyle(8x^2-4x)/(4x-2)=(4x(2x-1))/(2(2x-1))=\boxed{2x}`

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2.

`\displaystyle(8x-4)/(x+3)-(12x-20)/(2x+6)=(8x-4)/(x+3)-(4(3x-5))/(2(x+3))=(8x-4-2(3x-5))/(x+3)\\\\=(8x-4-6x+10)/(x+3)=(2x+6)/(x+3)=(2(x+3))/(x+3)=\boxed{2}`

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3.

`\displaystyle((2x+10)^7)/((x+5)^6)=((2(x+5))^7)/((x+5)^6)=2^7(x+5)^(7-6)=128(x+5)\\\\=\boxed{128x+640}`