Question

A triangle has sides of length: 372 +8, 202 + I, and a 3. What is the perimeter of the triangle? Recall that the perimeter is the sum of the sides, 52 + 2x + 5​

Answer 1

Given sides of the triangle:

• 3x^2 + 8,
• 2x^2 + x, and
• x - 3.

We know that the perimeter of a triangle is the sum of all the sides of a triangle.

Perimeter of the triangle,

= 3x^2 + 8 + 2x^2 + x + x - 3

= 3x^2 + 2x^2 + x + x + 8 - 3

= 5x^2 + 2x + 5

Therefore, the perimeter of the triangle is 5x^2 + 2x + 5. Hence, the option A is the correct answer.