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S = 2lw + 2wh + 2hl, solve for h (surface area of a rectangle)
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S = 2lw + 2wh + 2hl, solve for h (surface area of a rectangle)

User Rifinio
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2 Answers

20 votes
20 votes

Answer:


s = 2lw + 2wh + 2hl \\ s = 2(lw + wh + hl) \\ (s)/(2) = lw + wh + hl \\ (s)/(2) - lw = h(w + l) \\ h = ( (s)/(2) - lw)/(w + l) \\ thank \: you

User MouseWanted
by
3.0k points
13 votes
13 votes

Answer:

  • h = (S - 2lw)/(2w + 2l)

Explanation:

Given formula:

  • S = 2lw + 2wh + 2hl

Solve for h:

  • 2wh + 2lh = S - 2lw
  • h(2w + 2l) = S - 2lw
  • h = (S - 2lw)/(2w + 2l)
User Matlabgui
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2.5k points
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