Final answer:
Between 2009 and 2014, both Park A and Park B had the same change in population and the same average rate of growth of 26 swallows per year.
Step-by-step explanation:
To find the rates of change in population for both parks between 2009 and 2014, we need to determine the slopes of the population curves during that time period. By examining the graphs provided, we can see that Park A had a population of approximately 350 swallows in 2009 and around 480 swallows in 2014. The change in population is 480 - 350 = 130 swallows during that time period. Similarly, Park B had a population of approximately 250 swallows in 2009 and around 380 swallows in 2014. The change in population for Park B is 380 - 250 = 130 swallows. So both parks had the same change in population from 2009 to 2014.
To determine which park showed faster growth during those years, we need to calculate the average rate of change for each park. The average rate of change is equal to the change in population divided by the number of years. The number of years from 2009 to 2014 is 2014 - 2009 = 5. The average rate of change for Park A is 130 swallows / 5 years = 26 swallows/year. The average rate of change for Park B is also 130 swallows / 5 years = 26 swallows/year. Therefore, both parks showed the same rate of growth during those years.