Question

A =
`(1)/(2)`h(B + b) Solve for B.
(area of a trapezoid)

Answer 1

Explanation:

`a = (1)/(2) h( \beta + b) \\ 2a = h( \beta + b) \\ (2a)/(h) = \beta + b \\ (2a)/(h) - b = \beta \\ thank \: you`

Answer 2

A = 1/2h(B+b)

Multiply both sides by 2:

2A = h(B+b)

Divide both sides by h:

2A/h = (B+b)

Subtract b from both sides:

2A/h - b = B

Switch the equation so B is on the left side:

B = 2A/h - b