Question

FeSO4+K2Cr2O7+H2SO4+Fe2(SO4)3+Cr2(SO4)3+K2SO4+H2O Please balance the equation through Oxidation number method of redox reaction with the process .How is it balanced with full procedure.

Answer 1

The equation
`FeSO_4 + K_2Cr_2O_7 + H_2SO_4 \rightarrow Fe_2(SO_4)^3 + Cr_2(SO_4)^3 + K_2SO_4 + H_2O` is balanced by separating into half-reactions for oxidation and reduction, balancing the atoms and charges in those reactions, and then combining them into a full balanced chemical equation.

Step-by-step explanation:

To balance the equation
`FeSO_4 + K_2Cr_2O_7 + H_2SO_4 \rightarrow Fe_2(SO_4)^3 + Cr_2(SO_4)^3 + K_2SO_4 + H_2O` by the oxidation number method, we need to follow a series of steps. Firstly, we identify and write the half-reactions for oxidation and reduction. Oxidation involves Fe2+ turning into Fe3+ and reduction involves Cr2O72- turning into Cr3+. We then balance the atoms that are involved in the oxidation and reduction separately, except for oxygen and hydrogen. Oxygen is balanced by adding H2O on the side where it is deficient and hydrogen is balanced by adding H+. After that, we balance the charges by adding electrons. Once both half-reactions are balanced separately, we combine them by making the number of electrons gained in the reduction half-reaction equal to the number of electrons lost in the oxidation half-reaction. Finally, we add all species together and balance remaining ions and molecules, like K+ and SO42-, to have the atoms and charges balanced on both sides of the equation.

Answer 2

See explanation

Step-by-step explanation:

In every redox process, there is an oxidizing agent (that accepts electrons) and a reducing agent* the looses electrons).

For a moment let us ignore the spectator ions and focus on Fe^2+, Cr2O7^2- and H^+.

Hence,

Reduction half equation;

Cr2O7^2-(aq) + 14H^+(aq) + 6e ---------> 2Cr^+(aq) + 7H2O(l)

Oxidation half equation;

6Fe^2+(aq) --------> 6Fe^3+(aq) + 6e

Overall redox reaction equation;

Cr2O7^2-(aq) + 14H^+(aq) + 6Fe^2+(aq) ------>2Cr^+(aq) + 6Fe^3+(aq)

From here the balanced molecular reaction equation is;

K2Cr2O7(aq) + 6FeSO4(aq) + 7H2SO4(aq) -------> Cr2(SO4)3(aq) + 3Fe2(SO4)3(aq) + K2SO4(aq) + 7H2O(l)