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A performer walks up a tightrope from the ground to the top of a pole that is 18 feet tall. How many feet does the performer walk to get to the top of the pole? Round your answer to the nearest tenth is necessary.

A performer walks up a tightrope from the ground to the top of a pole that is 18 feet-example-1

2 Answers

9 votes

Answer:

36

Explanation:

this is a 30 60 90 triangle. u can search up the concept of it bc u need a diagram to understand.

but basically the answer is 36.

User Remi Cuingnet
by
6.9k points
12 votes

The performer walks 36 ft to get to the top of the pole.

How to determine the distance covered by the performer

From the figure

The triangle is a right angled triangle

The height of the wall is opposite to angle 30⁰

The rope form the hypotenuse of the the triangle

Using sine ratio

Sinθ = opposite/hypotenuse

θ = 30⁰

hypotenuse = length of rope = L

opposite = height of wall

opposite = 18 ft

Therefore,

Sin30 = 18/L

Lsin30 = 18

L = 18/sin30

L = 18/0.5

L = 36 feet

The performer walks 36 ft to get to the top of the pole.

User Dunsin Olubobokun
by
6.8k points