Question

Question 12 please
Tan(a)/
Sec(a)-cos(a)

Answer 1

Explanation:

`(tan ~\alpha )/(sec~\alpha -cos~\alpha ) \\=((sin~\alpha )/(cos~\alpha ) )/((1)/(cos~\alpha ) -cos~\alpha ) \\multiply~numerator~and~denominator~by~cos~\alpha \\=(sin~\alpha )/(1-cos^2~\alpha )=(sin~\alpha )/(sin ^2~\alpha ) \\=(1)/(sin~\alpha ) \\=cosec~\alpha`