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Find the equation of a line which passes through the points (3, -9) and (6, -18)

PLEAAASE provide whole answer not just slope

User ZSG
by
3.2k points

1 Answer

8 votes

Explanation:

Given points

( 3 , - 9) and ( 6 , - 18 )

The equation of the line is

y - y1 = ( y2 - y1 / x2 - x1 ) ( x - x1)

y + 9 = ( - 18 + 9 / 6 - 3 ) ( x - 3 )

y + 9 = ( - 9 / 3 ) ( x - 3 )

y + 9 = - 3 ( x - 3 )

y + 9 + 3( x - 3 ) = 0

y + 9 + 3x - 9 = 0

y + 3x = 0

Is the required equation.

Hope it will help :)♡♥

User Danilonet
by
3.5k points