Question

How many gallons of a 60% antifreeze solution must be mixed with 80 gallons of 10% antifreeze to get a mixture that is 50% antifreeze? Use the

six-step method.
You need gallons.

Answer 1

I am not sure what the six-step method looks looks like but if you use x gallons of 60% solution
the amount of antifreeze in the mixture = 0.6x + 8 gallons
This needs to be 50% of the total quantity in the mixture, x + 80
0.6x + 8 = 0.5(x + 80)
0.6x + 8 = 0.5x + 40
0.6 - 0.5 = 40 - 8
0.1x = 32
x = 32 x 10 = 320 gallons